Some basic doubts about blocking

Since i start playing Jyhad ... (A long time ago, in a galaxy far far away....) I allways seen two different ways of perform and resolve a Block. - Only one minion can attempt to block, and if that minion could not block, the action is succesful. I.e. a bleeding minion A (0 stealth)and a blocking minion B (0 intercept). With this stats, the minion B is declared as Blocker, but minion A play some stealth, and the minion B could not play intercept, so the action is succesfull. - Any number of minions could try a block. I.e. a bleeding minion A (0 stealth), a blocking minion B (0 intercept) and another blocking minion C with a raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the minion A plays a +1 stealth. As none of the blocking minion could increase his intercept, the minion B blocking Fails, but as minion C is ready, C is declared as new blocker Wich one of those ways is teh correct one?? Thnaks

In message <%7mX6.12809$pb1.4...@www.newsranger.com>, Athenethor <nos...@newsranger.com> writes >- Any number of minions could try a block. I.e. a bleeding minion A (0 >stealth), a blocking minion B (0 intercept) and another blocking minion C with a >raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the >minion A plays a +1 stealth. As none of the blocking minion could increase his >intercept, the minion B blocking Fails, but as minion C is ready, C is declared >as new blocker This is the correct way. Remember, of course, that just because a new blocker turns up, A doesn't reset his stealth. A still has the +1 stealth he played against B, because that applies to the entire action. -- James Coupe PGP Key: 0x5D623D5D "You reinstall Dial-Up Networking. The Elf screams and becomes EBD690ECD7A1F an icon. *** CONGRATULATIONS! *** You completed the BT Internet B457CA213D7E6 Helpdesk training course in 15 out of a possible 9000 moves." 68C3695D623D5D

In article <LSfSJADz...@gratiano.zephyr.org.uk>, James Coupe says... > >In message <%7mX6.12809$pb1.4...@www.newsranger.com>, Athenethor ><nos...@newsranger.com> writes >>- Any number of minions could try a block. I.e. a bleeding minion A (0 >>stealth), a blocking minion B (0 intercept) and another blocking minion C with a >>raven spy (1 int.). With this stats. minion B is assignmed as blocker, but the >>minion A plays a +1 stealth. As none of the blocking minion could increase his >>intercept, the minion B blocking Fails, but as minion C is ready, C is declared >>as new blocker > >This is the correct way. > >Remember, of course, that just because a new blocker turns up, A doesn't >reset his stealth. > >A still has the +1 stealth he played against B, because that applies to >the entire action. > First, thanks for the answer, and now, another question: I think that the same could be applied to cards like Form of Mist, Elder Impersonation ... this card re-open the blocker assignment stage (Form of mist type) or remove one blocker from the ready list (Elder Imp. type) Is this correct?? Athenethor

[ quoted text not captured ] The latter. [6.2.2.1] -- LSJ (vte...@white-wolf.com) V:TES Net.Rep for White Wolf, Inc. Links to revised rulebook, rulings, errata, and tournament rules: http://www.white-wolf.com/vtes/

Athenethor wrote: > I think that the same could be applied to cards like Form of Mist, Elder > Impersonation ... this card re-open the blocker assignment stage (Form of mist > type) or remove one blocker from the ready list (Elder Imp. type) > Is this correct?? Yes. [ quoted text not captured ]