Assuming I have two minions in play with Camera Phone, and one of them
takes his Camera Phone bleed action, gets blocked, and plays Red
Herring, can the other take his own Camera Phone's bleed action?
I assume on the basis that the actions would not count as the same
action for NRA (action allowed by card in play is NRA'd per copy of
the card that allows the action), despite the fact that NRA seperately
prohibits taking actions with more than one Camera Phone in a turn by
way of prohibiting multiple bleeds.
Is this right?
-witness1
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Yes. The same reason that the second minion couldn't Mask the first's Camera
Phone bleed: the two bleeds are different actions (because they're provided by
different cards in play).
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And presumably (just for clarity): If minion A has a Camera Phone and
bleeds, is blocked, plays Red Herring, then the phone is Heidelberg'd
to Minion B, Minion B cannot use it to bleed, correct (because it's
the same card in play, and thus the same action)?
- D.J.
Meej wrote:
> On Jul 25, 3:32 pm, LSJ <vtes...@white-wolf.com> wrote:>> witness1 wrote:>>> Assuming I have two minions in play with Camera Phone, and one of them
>>> takes his Camera Phone bleed action, gets blocked, and plays Red
>>> Herring, can the other take his own Camera Phone's bleed action?
>>> I assume on the basis that the actions would not count as the same
>>> action for NRA (action allowed by card in play is NRA'd per copy of
>>> the card that allows the action), despite the fact that NRA seperately
>>> prohibits taking actions with more than one Camera Phone in a turn by
>>> way of prohibiting multiple bleeds.
>>> Is this right?>> Yes. The same reason that the second minion couldn't Mask the first's Camera
>> Phone bleed: the two bleeds are different actions (because they're provided by
>> different cards in play).>
> And presumably (just for clarity): If minion A has a Camera Phone and
> bleeds, is blocked, plays Red Herring, then the phone is Heidelberg'd
> to Minion B, Minion B cannot use it to bleed, correct (because it's
> the same card in play, and thus the same action)?
Correct.