rec.games.trading-cards.jyhad

Mass Killing

5 messages from 2 participants · 13 February 2002
original thread on Google Groups

Orpheus

Hello, let's say I call a vote (Domain Challenge for instance) which kills at the same time my prey and grand'prey. Does my prey benefit for the death of my prey, and therefore not die, or does everybody die and I get 12 pool / 2VPs ? -- Yours, Orpheus, Prince of Marseille http://no.exit.free.fr (onlive novel) http://cypheranima.free.fr (goth band) news://news.zoo-logique.org/VTES-francophone audio...@yahoogroups.com

LSJ

Orpheus wrote: > let's say I call a vote (Domain Challenge for instance) which kills at the > same time my prey and grand'prey. Does my prey benefit for the death of my > prey, and therefore not die, or does everybody die and I get 12 pool / 2VPs See The "Exception" paragraph in section 9.1 of the rules. -- LSJ (vte...@white-wolf.com) V:TES Net.Rep for White Wolf, Inc. Links to revised rulebook, rulings, errata, and tournament rules: http://www.white-wolf.com/vtes/

Orpheus

> Orpheus wrote: > > let's say I call a vote (Domain Challenge for instance) which kills at the > > same time my prey and grand'prey. Does my prey benefit for the death of my > > prey, and therefore not die, or does everybody die and I get 12 pool / 2VPs > > See The "Exception" paragraph in section 9.1 of the rules. Ok, thank you. So, you have to consider very carefully what you're about to do... What cards allow you to untap someone else's minions ?

LSJ

Orpheus wrote: > What cards allow you to untap someone else's minions ? Alexandra Moncada Angela Preston Panacea Patronage Precognizant Mobility Rayzeel's Song (And miscellaneous cards like Meld with the Land, but you're probably not looking for those types). [ quoted text not captured ]

Orpheus

> Orpheus wrote: > > What cards allow you to untap someone else's minions ? > > Alexandra > Moncada > Angela Preston > Panacea > Patronage > Precognizant Mobility > Rayzeel's Song > > (And miscellaneous cards like Meld with the Land, but you're > probably not looking for those types). Ok, thank you.