rec.games.trading-cards.jyhad

To LSJ, about contested card on a burned minion: what happens?

4 messages from 3 participants · 13 September 2010 – 14 September 2010
original thread on Google Groups

Vinicius Coelho de Almeida

Howdy. I couldn't find an answer for my question using google.groups. So, here it is: A minion that I control has a contested Pentex Subversion; the other one Pentex Subversion is on one of my prey's minion (say, 'A'). In my prey's turn, he burned my pentexed minion with another minion (say, 'B'). His minion 'A' was still untapped. What happens with the Pentex on 'A'? There was no yielding, then section 4.1 (below) would not be applicable, would it? So, is it contested yet? Is it activated? Out of play, because there's no minion to put the Pentex on? Thanks in advance, Vinícius. "Pentex(TM) Subversion Master Unique master. Put this card on any ready minion. The minion with this card cannot take actions and cannot block actions. This card may be burned by any other minion as a (D) action." "4.1. Contested Cards Some of the cards in the game represent unique resources, such as specific locations, equipment or people. These cards will be identified as "unique" in their card text. In addition, all crypt cards represent unique minions. If more than one unique card with the same name is brought into play, that means control of the card is being contested. For the duration of the contest, all of the contested cards are turned face down and are out of play. If another unique card with the same name is brought into play, it is immediately contested and turned face down as well. The cost to contest a card is one pool, which you pay during each of your untap phases. Instead of paying the cost to contest the card, you may choose to yield the card. A yielded card is burned. Any cards or counters stacked on the yielded card are also burned. If all other cards contesting your unique card are yielded, then the card is untapped and turned face up during your next untap phase, ending the contest. Be careful about putting duplicates of the same unique cards in your deck. You can't control more than one of the same unique card at a time, and you cannot contest cards with yourself (if some effect would force you to contest a card with yourself, then you simply burn the incoming copy of the unique card). On the other hand, you may wish to have a second copy handy in case the first is burned. "

floppyzedolfin

On 13 sep, 23:15, Vinicius Coelho de Almeida <mak...@dcc.ufmg.br> wrote: > Howdy. > > I couldn't find an answer for my question using google.groups. So, here it > is: > A minion that I control has a contested Pentex Subversion; the other > one Pentex Subversion is on one of my prey's minion (say, 'A'). In my > prey's turn, he burned my pentexed minion with another minion (say, 'B'). > His minion 'A' was still untapped. What happens with the Pentex on 'A'? > There was no yielding, then section 4.1 (below) would not be applicable, > would it? So, is it contested yet? Is it activated? Out of play, because > there's no minion to put the Pentex on? It comes back to play during its controller's untap phase. All other copies (there's 0 of them in play) have been yielded. [ quoted text not captured ]

LSJ

On Sep 14, 1:49 am, floppyzedolfin <floppyzedol...@gmail.com> wrote: > On 13 sep, 23:15, Vinicius Coelho de Almeida <mak...@dcc.ufmg.br> > wrote: > > > Howdy. > > > I couldn't find an answer for my question using google.groups. So, here it > > is: > > A minion that I control has a contested Pentex Subversion; the other > > one Pentex Subversion is on one of my prey's minion (say, 'A'). In my > > prey's turn, he burned my pentexed minion with another minion (say, 'B'). > > His minion 'A' was still untapped. What happens with the Pentex on 'A'? > > There was no yielding, then section 4.1 (below) would not be applicable, > > would it? So, is it contested yet? Is it activated? Out of play, because > > there's no minion to put the Pentex on? > > It comes back to play during its controller's untap phase. > All other copies (there's 0 of them in play) have been yielded. Correct. [ quoted text not captured ]

Vinicius Coelho de Almeida

Thanks for the answers. [ quoted text not captured ]