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At least one of vampires 4-6 has to be the same as one of vampires a-d
for player A to play betrayer "against" player B.
For example(s):
1) vamp 4 is the same as vamp a.
Player A plays betrayer and says "Player B, one of your vampires is a
betrayer." (noting to herself that vamp a is the one that allows her to
play the card at all).
Player B would then, after losing one pool, choose to pay one pool to
attempt to guess the betrayer. If she guesses that vamp a is the betrayer
(by name), then the Betrayer card is burned.
2) vamp 4 and vamp 5 are the same as vamp a.
Everything plays as in example 1) above.
3) vamp 4 is the same as vamp a and vamp 5 is the same as vamp b.
Player A plays betrayer and says "Player B, one of your vampires is a
betrayer." (noting to herself that vamp a is the one that allows her
to play the card at all *or* noting that vamp b is the one that allows
her to play the card).
Player B would then, after losing one pool, choose to pay one pool to
attempt to guess the betrayer. If she guesses correctly (guessing vamp
a if he was the one that player A had noted *or* guessing vamp b if
he was instead the one that player A had noted), then the Betrayer card
is burned.
--
LSJ (vte...@wizards.com) VTES Net.Rep for Wizards of the Coast.
Links to revised rulebook, rulings, errata, and DCI (tournament) rules:
http://www.wizards.com/VTES/VTES_Rules.html
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