J wrote:
> There are 5 players still in the game.
> Meth A has 3 pool, his prey Meth B has 4 pool.
>
> Can Meth A call a Parity Shift targeting B, even though X is not equal
> to the Meth's in the game, or would Meth B have to be on 5+ pool for
> the shift to be legal?
>
Legal. Meth B simply loses 5 pool and is ousted. UNLESS Meth C plays
Life Boon for at least 2 to save Meth B (because Meth B is at -1 pool
when they are ousted). The targeting rules for PS are simply who has
more pool than the calling Methuselah. How much they have is
irrelevant, except as it relates to how much the calling Meth has.
BUT - I am usually wrong on this stuff, so I would wait for James, Jeff
or of course LSJ (whose call tag I put in the subject...)
best -
chris
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